Solved: In 29 and 30 use (20) or (21) to obtain the given
Chapter 6, Problem 30E(choose chapter or problem)
In Problems 29 and 30 use (20) or (21) to obtain the given result.
\(J_{0}^{\prime}(x)=J_{-1}(x)=-J_{1}(x)\)
Text Transcription:
J_0^prime(x)=J_-1(x)=-J_1(x)
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