Solution Found!
Figure 7.1.4 suggests, but does not prove, that the
Chapter 7, Problem 49E(choose chapter or problem)
QUESTION:
Figure 7.1.4 suggests, but does not prove, that the function \(f(t)=e^{t^{2}}\) is not of exponential order. How does the observation that \(t^{2}\) > In \(M+c t\), for M > 0 and t sufficiently large, show that \(e^{t^{2}}\) > \(M e^{c t}\) for any c?
Text Transcription:
f(t)=e^t^2
t^2
M+ct
e^t^2
M e^ct
Questions & Answers
QUESTION:
Figure 7.1.4 suggests, but does not prove, that the function \(f(t)=e^{t^{2}}\) is not of exponential order. How does the observation that \(t^{2}\) > In \(M+c t\), for M > 0 and t sufficiently large, show that \(e^{t^{2}}\) > \(M e^{c t}\) for any c?
Text Transcription:
f(t)=e^t^2
t^2
M+ct
e^t^2
M e^ct
ANSWER:Step 1 of 2
Given that
We have to show that for any c?