A long solenoid has a diameter of 12.0 cm. When a current i exists in its windings, a uniform magnetic field of magnitude B = 30.0 mT is produced in its interior. By decreasing i, the field is caused to decrease at the rate of 6.50 mT/s. Calculate the magnitude of the induced electric field (a) 2.20 cm and (b) 8.20 cm from the axis of the solenoid.
Chapter 22: Magnetism Bar magnets have poles on opposite sides called north poles and south poles. They act as normal magnets (like attracts like, opposites repel) Magnetic field lines exit from the north pole and enter from the south. F= |q|vBsin(thet) Magnitude of the Magnetic Force: o SI unit is newton (N) o q is the charge o v is the velocity o B is the magnetic field Right hand rule o Source: Google images/ boundless.com Since the magnetic force is always perpendicular to the direction of motion, the path of a particle is always circular. o The radius is travels: r=(mv)/( |q|B) Magnetic force on a current carrying wire: F=ILBsin (