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Solved: A long solenoid has a diameter of 12.0 cm. When a

Fundamentals of Physics Extended | 9th Edition | ISBN: 9780470469088 | Authors: David Halliday ISBN: 9780470469088 189

Solution for problem 37 Chapter 30

Fundamentals of Physics Extended | 9th Edition

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Fundamentals of Physics Extended | 9th Edition | ISBN: 9780470469088 | Authors: David Halliday

Fundamentals of Physics Extended | 9th Edition

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Problem 37

A long solenoid has a diameter of 12.0 cm. When a current i exists in its windings, a uniform magnetic field of magnitude B = 30.0 mT is produced in its interior. By decreasing i, the field is caused to decrease at the rate of 6.50 mT/s. Calculate the magnitude of the induced electric field (a) 2.20 cm and (b) 8.20 cm from the axis of the solenoid.

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Chapter 22: Magnetism Bar magnets have poles on opposite sides called north poles and south poles. They act as normal magnets (like attracts like, opposites repel) Magnetic field lines exit from the north pole and enter from the south. F= |q|vBsin(thet) Magnitude of the Magnetic Force: o SI unit is newton (N) o q is the charge o v is the velocity o B is the magnetic field Right hand rule o Source: Google images/ boundless.com Since the magnetic force is always perpendicular to the direction of motion, the path of a particle is always circular. o The radius is travels: r=(mv)/( |q|B) Magnetic force on a current carrying wire: F=ILBsin (

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Chapter 30, Problem 37 is Solved
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Textbook: Fundamentals of Physics Extended
Edition: 9
Author: David Halliday
ISBN: 9780470469088

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Solved: A long solenoid has a diameter of 12.0 cm. When a