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In Ex. 3.2 we assumed that the conducting sphere was

Introduction to Electrodynamics | 4th Edition | ISBN: 9780321856562 | Authors: David J. Griffiths ISBN: 9780321856562 45

Solution for problem 9P Chapter 3

Introduction to Electrodynamics | 4th Edition

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Introduction to Electrodynamics | 4th Edition | ISBN: 9780321856562 | Authors: David J. Griffiths

Introduction to Electrodynamics | 4th Edition

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Problem 9P

In Ex. 3.2 we assumed that the conducting sphere was grounded (V = 0). But with the addition of a second image charge, the same basic model will handle the case of a sphere at any potential V0 (relative, of course, to infinity). What charge should you use, and where should you put it? Find the force of attraction between a point charge q and a neutral conducting sphere.

Reference example 3.2

A point charge q is situated a distance a from the center of a grounded conducting sphere of radius R (Fig. 3.12). Find the potential outside the sphere.

Reference figure 3.12

Step-by-Step Solution:

Step 1 of 4</p>

We have to find the potential at the outside of the sphere and The force of attraction between charge and neutral conducting sphere..

Step 2 of 4</p>

The sphere is  equipotential, so if we place the second charge , the potential increases at the centre of sphere.

The new  potential is,

 

is the permittivity of the medium.

 is the radius of the sphere

According to gauss law total charge on the sphere is,

Step 3 of 4

Chapter 3, Problem 9P is Solved
Step 4 of 4

Textbook: Introduction to Electrodynamics
Edition: 4
Author: David J. Griffiths
ISBN: 9780321856562

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In Ex. 3.2 we assumed that the conducting sphere was

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