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Get Full Access to Introduction To Electrodynamics - 4 Edition - Chapter 5 - Problem 19p
Get Full Access to Introduction To Electrodynamics - 4 Edition - Chapter 5 - Problem 19p

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# In calculating the current enclosed by an Amperian loop, ISBN: 9780321856562 45

## Solution for problem 19P Chapter 5

Introduction to Electrodynamics | 4th Edition

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Problem 19P

Problem 19P

In calculating the current enclosed by an Amperian loop, one must, in general, evaluate an integral of the form The trouble is, there are infinitely many surfaces that share the same boundary line. Which one are we supposed to use?

Step-by-Step Solution:

Step 1 of  1

We are suppose to find which surface are we going to use in  evaluating the current enclosed by an Amperian loop as there are infinitely many surfaces.  For a field ( ) which is divergence-less it implies that    is independent of surface, for any given boundary line.

Now, is divergence-less which it is for a steady current.

Therefore, we can use any surface to evaluate the current enclosed by an Amperian loop.

Step 2 of 1

##### ISBN: 9780321856562

The answer to “In calculating the current enclosed by an Amperian loop, one must, in general, evaluate an integral of the form The trouble is, there are infinitely many surfaces that share the same boundary line. Which one are we supposed to use?” is broken down into a number of easy to follow steps, and 40 words. This textbook survival guide was created for the textbook: Introduction to Electrodynamics , edition: 4. Since the solution to 19P from 5 chapter was answered, more than 423 students have viewed the full step-by-step answer. This full solution covers the following key subjects: amperian, boundary, Calculating, current, enclosed. This expansive textbook survival guide covers 12 chapters, and 550 solutions. Introduction to Electrodynamics was written by and is associated to the ISBN: 9780321856562. The full step-by-step solution to problem: 19P from chapter: 5 was answered by , our top Physics solution expert on 07/18/17, 05:41AM.

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