Suppose a magnetic monopole qm passes through a resistanceless loop of wire with self-inductance L. What current is induced in the loop?
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PHYSICS 2401 WEEK 8 Chapter 28 DC Circuits Ideal Battery: Remember : Ph= I * R = V /R = V*I Model of non-ideal battery (real life) r = internal resistance ε= open current voltage Isc = ε /r comes from R = V/I V t I*R =L ε - I*r Battery Pb= P h 2* 2* ε*I = I r + I R * * ε = I r + I RL EX. A battery with ε = 10 V, internal resistance of 1Ώ, connected to R = 4Ώ. Find I. L Pb= P h 2* 2* ε*I = I r + I R I = ε/(r R L I = 10/(1+4) I=2 A EX. A battery connected to a R L,1= 10 Ώ, has V t 35V. When connected to a R L,2= 25Ώ, has V t 39V. Find ε,r. 1 = V/t L,1= 35V/10Ώ = 3.5A 2 = V/t L
Textbook: Introduction to Electrodynamics
Author: David J. Griffiths
This textbook survival guide was created for the textbook: Introduction to Electrodynamics , edition: 4. The answer to “Suppose a magnetic monopole qm passes through a resistanceless loop of wire with self-inductance L. What current is induced in the loop?” is broken down into a number of easy to follow steps, and 22 words. Introduction to Electrodynamics was written by and is associated to the ISBN: 9780321856562. Since the solution to 39P from 7 chapter was answered, more than 552 students have viewed the full step-by-step answer. This full solution covers the following key subjects: Loop, monopole, inductance, current, magnetic. This expansive textbook survival guide covers 12 chapters, and 550 solutions. The full step-by-step solution to problem: 39P from chapter: 7 was answered by , our top Physics solution expert on 07/18/17, 05:41AM.