Solution Found!
(a) A particle of charge q moves in a circle of radius R
Chapter 11, Problem 17P(choose chapter or problem)
Problem 17P
(a) A particle of charge q moves in a circle of radius R at a constant speed v. To sustain the motion, you must, of course, provide a centripetal force mv2/R; what additional force (Fe) must you exert, in order to counteract the radiation reaction? [It’s easiest to express the answer in terms of the instantaneous velocity v.] What power (Pe) does this extra force deliver? Compare Pe with the power radiated (use the Larmor formula).
(b) Repeat part (a) for a particle in simple harmonic motion with amplitude A and angular frequency Explain the discrepancy.
(c) Consider the case of a particle in free fall (constant acceleration g). What is the radiation reaction force? What is the power radiated? Comment on these results.
Questions & Answers
QUESTION:
Problem 17P
(a) A particle of charge q moves in a circle of radius R at a constant speed v. To sustain the motion, you must, of course, provide a centripetal force mv2/R; what additional force (Fe) must you exert, in order to counteract the radiation reaction? [It’s easiest to express the answer in terms of the instantaneous velocity v.] What power (Pe) does this extra force deliver? Compare Pe with the power radiated (use the Larmor formula).
(b) Repeat part (a) for a particle in simple harmonic motion with amplitude A and angular frequency Explain the discrepancy.
(c) Consider the case of a particle in free fall (constant acceleration g). What is the radiation reaction force? What is the power radiated? Comment on these results.
ANSWER:
a.)
Step 1 of 6
We have to find the additional force that must be exerted, in order to counteract the radiation reaction force from a particle of charge which is moving in a circle of radius at a constant speed and also the power delivered by this extra force.
The additional force to counteract the radiation reaction force can be found using the Abraham- Lorentz formula for the radiation reaction force.
where, is the acceleration of the charge.
Now for a circular motion,
so,
Thus,
Therefore, the additional force that must be exerted is