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y 2 sec x 61

Trigonometry | 7th Edition | ISBN: 9781111826857 | Authors: Charles P. McKeague ISBN: 9781111826857 186

Solution for problem 60 Chapter 4.4

Trigonometry | 7th Edition

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Trigonometry | 7th Edition | ISBN: 9781111826857 | Authors: Charles P. McKeague

Trigonometry | 7th Edition

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Problem 60

y 2 sec x 61

Step-by-Step Solution:
Step 1 of 3

MAT 211­ Lecture 6­ 15.3 & 15.4 Section 15.3 Homework #8: ln(x,y)= x​ +y​2­y​x­2 lnx= 0 & lny= 0 1st Derivative:​ lnx= 2x­y​ lny= 2y­2yx I. 2x­y​=0 ­­­­­­­> x=1 2­y​=0 2=y​ y=­ 2 2​ 2y­2yx=0 ­­­­­­­> y=0 2x­y​ =0 2x­0=0 x=0 II. 2y(1­x)= 0 y=0 & x=1 Critical Points: (0,0); (1, ­ 2); (1, + 2) 2nd Derivative:​ lnxx= 2 lnxx (0,0)= 2 lnyy= 2­2x lnyy (0,0)= 2 lnxy= ­2y lnxy (0,0)= 0 H(0,0)= 2 * 2 ­ 0= 4 Since lnxx= 2>0, then we have a relative minimum at (0,0). ­Critical point at (1, ­ 2) : lnxx (1, ­ 2) =2 √

Step 2 of 3

Chapter 4.4, Problem 60 is Solved
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Textbook: Trigonometry
Edition: 7
Author: Charles P. McKeague
ISBN: 9781111826857

The full step-by-step solution to problem: 60 from chapter: 4.4 was answered by , our top Math solution expert on 12/27/17, 07:46PM. This textbook survival guide was created for the textbook: Trigonometry, edition: 7. This full solution covers the following key subjects: . This expansive textbook survival guide covers 85 chapters, and 4184 solutions. Since the solution to 60 from 4.4 chapter was answered, more than 238 students have viewed the full step-by-step answer. Trigonometry was written by and is associated to the ISBN: 9781111826857. The answer to “y 2 sec x 61” is broken down into a number of easy to follow steps, and 5 words.

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y 2 sec x 61