If A and B are mutually exclusive events and P( B) > 0,

Chapter 2, Problem 83E

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QUESTION:

If  and  are mutually exclusive events and \(P(B)>0\), show that \(P(A \mid A \cup B)=\frac{P(A)}{P(A)+P(B)}\)

Equation Transcription:

Text Transcription:

P(B)>0

P(A|AUB)=P(A) over P(A)+P(B)

Questions & Answers

QUESTION:

If  and  are mutually exclusive events and \(P(B)>0\), show that \(P(A \mid A \cup B)=\frac{P(A)}{P(A)+P(B)}\)

Equation Transcription:

Text Transcription:

P(B)>0

P(A|AUB)=P(A) over P(A)+P(B)

ANSWER:

Solution:

Step 1 of 2:

If A and B are mutually exclusive events and P(B)>0 we have to show that

       P( =  


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