Solution Found!
If A and B are mutually exclusive events and P( B) > 0,
Chapter 2, Problem 83E(choose chapter or problem)
QUESTION:
If and are mutually exclusive events and \(P(B)>0\), show that \(P(A \mid A \cup B)=\frac{P(A)}{P(A)+P(B)}\)
Equation Transcription:
Text Transcription:
P(B)>0
P(A|AUB)=P(A) over P(A)+P(B)
Questions & Answers
QUESTION:
If and are mutually exclusive events and \(P(B)>0\), show that \(P(A \mid A \cup B)=\frac{P(A)}{P(A)+P(B)}\)
Equation Transcription:
Text Transcription:
P(B)>0
P(A|AUB)=P(A) over P(A)+P(B)
ANSWER:
Solution:
Step 1 of 2:
If A and B are mutually exclusive events and P(B)>0 we have to show that
P( =