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The maximum patent life for a new drug is 17 years.
Chapter 3, Problem 14E(choose chapter or problem)
The maximum patent life for a new drug is 17 years. Subtracting the length of time required by the FDA for testing and approval of the drug provides the actual patent life for the drug—that is, the length of time that the company has to recover research and development costs and to make a profit. The distribution of the lengths of actual patent lives for new drugs is given below:
\(\begin{array}{c|ccccccccccc} \text { Years, } y & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 \\ \hline p(y) & .03 & .05 & .07 & .10 & .14 & .20 & .18 & .12 & .07 & .03 & .01 \end{array}\)
a Find the mean patent life for a new drug.
b Find the standard deviation of Y = the length of life of a randomly selected new drug.
c What is the probability that the value of Y falls in the interval \(\mu \pm 2 \sigma\)?
Questions & Answers
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QUESTION:
The maximum patent life for a new drug is 17 years. Subtracting the length of time required by the FDA for testing and approval of the drug provides the actual patent life for the drug—that is, the length of time that the company has to recover research and development costs and to make a profit. The distribution of the lengths of actual patent lives for new drugs is given below:
\(\begin{array}{c|ccccccccccc} \text { Years, } y & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 \\ \hline p(y) & .03 & .05 & .07 & .10 & .14 & .20 & .18 & .12 & .07 & .03 & .01 \end{array}\)
a Find the mean patent life for a new drug.
b Find the standard deviation of Y = the length of life of a randomly selected new drug.
c What is the probability that the value of Y falls in the interval \(\mu \pm 2 \sigma\)?
ANSWER:Step 1 of 4
The distribution of the lengths of actual patent lives for the new drug table is given below.
\(\begin{array}{|r|r|} \hline \text { Years } & \text { p(y) } \\ \hline 3 & 0.03 \\ \hline 4 & 0.05 \\ \hline 5 & 0.07 \\ \hline 6 & 0.1 \\ \hline 7 & 0.14 \\ \hline 8 & 0.2 \\ \hline 9 & 0.18 \\ \hline 10 & 0.12 \\ \hline 11 & 0.07 \\ \hline 12 & 0.03 \\ \hline 13 & 0.01 \\ \hline \end{array}\)
Our goal is
a). We need to calculate the mean patent life for a new drug.
b). We need to calculate the standard deviation of Y.
c). We need to find the probability that the value of Y falls in the interval \(\mu \pm 2 \sigma\).
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