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Solved: If Y has a geometric distribution with success
Chapter 3, Problem 77E(choose chapter or problem)
QUESTION:
If Y has a geometric distribution with success probability p, show that
\(P(Y=\text { an odd integer })=\frac{p}{1-q^{2}}\).
Equation Transcription:
Text Transcription:
P(Y=an odd integer)=p over 1-q^2
Questions & Answers
QUESTION:
If Y has a geometric distribution with success probability p, show that
\(P(Y=\text { an odd integer })=\frac{p}{1-q^{2}}\).
Equation Transcription:
Text Transcription:
P(Y=an odd integer)=p over 1-q^2
ANSWER:
Solution:
Step 1 of 2:
Let X follows the Geometric distribution with p = probability of success and q = probability of failure.
The probability mass function is
P(X) = , x = 0, 1, 2,.....
The claim is show that the P(Y = an odd integer) =