If Y is a geometric random variable, define Y ? = Y ? 1.

Chapter 3, Problem 88E

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QUESTION:

Problem 88E

If Y is a geometric random variable, define Y ∗ = Y − 1. If Y is interpreted as the number of the trial on which the first success occurs, then Y ∗ can be interpreted as the number of failures before the first success. If Y ∗ = Y − 1, P(Y ∗ = y) = P(Y − 1 = y) = P(Y = y + 1) for y = 0, 1, 2, . . . . Show that

P ( Y ∗ = y) = q y p, y = 0, 1, 2, . . . .

The probability distribution of Y ∗ is sometimes used by actuaries as a model for the distribution of the number of insurance claims made in a specific time period.

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QUESTION:

Problem 88E

If Y is a geometric random variable, define Y ∗ = Y − 1. If Y is interpreted as the number of the trial on which the first success occurs, then Y ∗ can be interpreted as the number of failures before the first success. If Y ∗ = Y − 1, P(Y ∗ = y) = P(Y − 1 = y) = P(Y = y + 1) for y = 0, 1, 2, . . . . Show that

P ( Y ∗ = y) = q y p, y = 0, 1, 2, . . . .

The probability distribution of Y ∗ is sometimes used by actuaries as a model for the distribution of the number of insurance claims made in a specific time period.

ANSWER:

Solution :

Step 1 of 1:

Given Y is a geometric random variable.

Let Y is interpreted as the number of the trial on which the first success occurs.

Let  is interpreted as the number of failures before the first success.

Our goal is:

We need to show that P()=

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