Solved: Figure 26-79 shows the circuit for a simple

Chapter , Problem 90

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Figure 26-79 shows the circuit for a simple sawtooth oscillator.At time t = 0, its switch S is closed. The neon bulb hasinitially infinite resistance until the voltage across it reaches90.0 V, and then it begins to conduct with very little resistance(essentially zero). It stops conducting (its resistance becomesessentially infinite) when the voltage drops down to 65.0 V.(a) At what time t\ does the neon bulb reach 90.0 V and startconducting? (b) At what time t2 does the bulb reach 90.0 Vfor a second time and again become conducting? (c) Sketchthe sawtooth waveform between t = 0 and t = 0.70 s.

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