Show that the hypergeometric probability function

Chapter 3, Problem 212SE

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QUESTION:

Show that the hypergeometric probability function approaches the binomial in the limit as \(N \rightarrow \infty\) and \(p=r / N\) remains constant. That is, show that

\(\lim _{N \rightarrow \infty} \frac{\left(\begin{array}{l} r \\ y \end{array}\right)\left(\begin{array}{l} N-r \\ n-y \end{array}\right)}{\left(\begin{array}{l} N \\ n \end{array}\right)}=\left(\begin{array}{l} n \\ y \end{array}\right) p^{y} q^{n-y}\)

for \(p=r / N\) constant.

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QUESTION:

Show that the hypergeometric probability function approaches the binomial in the limit as \(N \rightarrow \infty\) and \(p=r / N\) remains constant. That is, show that

\(\lim _{N \rightarrow \infty} \frac{\left(\begin{array}{l} r \\ y \end{array}\right)\left(\begin{array}{l} N-r \\ n-y \end{array}\right)}{\left(\begin{array}{l} N \\ n \end{array}\right)}=\left(\begin{array}{l} n \\ y \end{array}\right) p^{y} q^{n-y}\)

for \(p=r / N\) constant.

ANSWER:

Step 1 of 4

Here we have to show that the Hypergeometric probability function approaches the Binomial probability function as \(N \rightarrow \infty\) and \(\mathrm{p}=\frac{r}{N}\).

That is we have to show that

\(\lim _{N \rightarrow \infty} \frac{\left(\begin{array}{l} r \\ y \end{array}\right)\left(\begin{array}{c} N-r \\ n-y \end{array}\right)}{\left(\begin{array}{c} N \\ n \end{array}\right)}=\left(\begin{array}{l} n \\ y \end{array}\right) p^{y} q^{n-y}\)

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