An argument similar to that of Exercise 4.168 can be used

Chapter 4, Problem 169SE

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QUESTION:

Problem 169SE

An argument similar to that of Exercise 4.168 can be used to show that if events are occurring in time according to a Poisson distribution with mean λt, then the inter arrival times between events have an exponential distribution with mean 1. If calls come into a police emergency center at the rate of ten per hour, what is the probability that more than 15 minutes will elapse between the next two calls?

Reference

The number of arrivals N at a supermarket checkout counter in the time interval from 0 to t follows a Poisson distribution with mean λt. Let T denote the length of time until the first arrival. Find the density function for T . [Note: P(T > t0) = P(N = 0 at t = t0).]

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QUESTION:

Problem 169SE

An argument similar to that of Exercise 4.168 can be used to show that if events are occurring in time according to a Poisson distribution with mean λt, then the inter arrival times between events have an exponential distribution with mean 1. If calls come into a police emergency center at the rate of ten per hour, what is the probability that more than 15 minutes will elapse between the next two calls?

Reference

The number of arrivals N at a supermarket checkout counter in the time interval from 0 to t follows a Poisson distribution with mean λt. Let T denote the length of time until the first arrival. Find the density function for T . [Note: P(T > t0) = P(N = 0 at t = t0).]

ANSWER:

Solution:

Step 1 of 2:

        Using the exercise 4.168, to show that if events are occurring in time according to a poisson distribution with mean

      Then given the inter arrival times between events an exponential distribution with mean

If calls come into a police emergency center at the rate of ten per hour.


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