Solution Found!
Let Y1 and Y2 denote the proportions of two different
Chapter 5, Problem 12E(choose chapter or problem)
Let \(Y_{1} \text { and } Y_{2}\) denote the proportions of two different types of components in a sample from a mixture of chemicals used as an insecticide. Suppose that \(Y_{1} \text { and } Y_{2}\) have the joint density function given by
\(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}
2, & 0 \leq y_{1} \leq 1,0 \leq y_{2} \leq 1,0 \leq y_{1}+y_{2} \leq 1, \\
0, & \text { elsewhere. }
\end{array}\right.
\)
(Notice that \(Y_{1}+Y_{2} \leq 1\) because the random variables denote proportions within the same sample.) Find
a \(\mathrm{P}\left(Y_1\le3/4,\ Y_2\le3/4\right)\).
b \(\mathrm{P}\left(Y_1\le1/2,\ Y_2\le1/2\right)\).
Equation Transcription:
Text Transcription:
Y_1 and Y_2
Y_1 and Y_2
f(y_1,y_2)=
2, 0</=y_11,0</=y_2</=1,0</=y_1+y_2</=1,
0, elsewhere.
Y_1+Y_2</=1
P(Y_1</=3/4,Y_2</=3/4)
P(Y_1</=1/2,Y_2</=1/2)
Questions & Answers
QUESTION:
Let \(Y_{1} \text { and } Y_{2}\) denote the proportions of two different types of components in a sample from a mixture of chemicals used as an insecticide. Suppose that \(Y_{1} \text { and } Y_{2}\) have the joint density function given by
\(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}
2, & 0 \leq y_{1} \leq 1,0 \leq y_{2} \leq 1,0 \leq y_{1}+y_{2} \leq 1, \\
0, & \text { elsewhere. }
\end{array}\right.
\)
(Notice that \(Y_{1}+Y_{2} \leq 1\) because the random variables denote proportions within the same sample.) Find
a \(\mathrm{P}\left(Y_1\le3/4,\ Y_2\le3/4\right)\).
b \(\mathrm{P}\left(Y_1\le1/2,\ Y_2\le1/2\right)\).
Equation Transcription:
Text Transcription:
Y_1 and Y_2
Y_1 and Y_2
f(y_1,y_2)=
2, 0</=y_11,0</=y_2</=1,0</=y_1+y_2</=1,
0, elsewhere.
Y_1+Y_2</=1
P(Y_1</=3/4,Y_2</=3/4)
P(Y_1</=1/2,Y_2</=1/2)
ANSWER:
Solution
Step 1 of 2
a) We have to find
Given that
=0, Otherwise
The joint distribution function is
Then
=
=2(3/4 )(1/4)+(1/2)
=(3/8)+(1/2)
=7/8
Hence =7/8