Solved: Suppose that the random variables Y1 and Y2 have

Chapter 5, Problem 32E

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QUESTION:

Suppose that the random variables \(Y_{1}\) and \(Y_{2}\) have joint probability density function, \(f\left(y_{1}, y_{2}\right)\), given by (see Exercise 5.14)

                           \(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}

6 y_{1}^{2} y_{2}, & 0 \leq y_{1} \leq y_{2}, y_{1}+y_{2} \leq 2, \\

0, & \text { elsewhere. }

\end{array}\right.

\)

a Show that the marginal density of \(Y_{1}\) is a beta density with \(\alpha=3\) and \(\beta=2\).

b Derive the marginal density of \(Y_{2}\).

c Derive the conditional density of \(Y_{2}\) given \(Y_{1}=y_{1}\).

d Find \(P\left(Y_{2}<1.1 \mid Y_{1}=.60\right)\).

Equation Transcription:

Text Transcription:

Y_1

Y_2

f(y_1,y_2)

f(y_1,y_2)=

6y_1^2 y_2, 0</=y_1</=y_2,y_1+y_2</=2,

0, elsewhere.

Y_1

alpha=3

beta=2

Y_2

Y_2

Y_1=y_1

P(Y_2<1.1|Y_1=.60)

Questions & Answers

QUESTION:

Suppose that the random variables \(Y_{1}\) and \(Y_{2}\) have joint probability density function, \(f\left(y_{1}, y_{2}\right)\), given by (see Exercise 5.14)

                           \(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}

6 y_{1}^{2} y_{2}, & 0 \leq y_{1} \leq y_{2}, y_{1}+y_{2} \leq 2, \\

0, & \text { elsewhere. }

\end{array}\right.

\)

a Show that the marginal density of \(Y_{1}\) is a beta density with \(\alpha=3\) and \(\beta=2\).

b Derive the marginal density of \(Y_{2}\).

c Derive the conditional density of \(Y_{2}\) given \(Y_{1}=y_{1}\).

d Find \(P\left(Y_{2}<1.1 \mid Y_{1}=.60\right)\).

Equation Transcription:

Text Transcription:

Y_1

Y_2

f(y_1,y_2)

f(y_1,y_2)=

6y_1^2 y_2, 0</=y_1</=y_2,y_1+y_2</=2,

0, elsewhere.

Y_1

alpha=3

beta=2

Y_2

Y_2

Y_1=y_1

P(Y_2<1.1|Y_1=.60)

ANSWER:

Solution :

Step 1 of 4:

Let and have joint density function.

Then the joint density function and  is

Our goal is:

a). We need to find the marginal density of is a beta density with and .

b). We need to derive the marginal density of .

c). We need to find derive the conditional density of .

d). We need to find the probability is less than 1.

a).

The marginal density function of a continuous random variable is

or

Where 0.

Therefore,

       0, otherwise

The beta distribution with and .

Then,

B()= 

We substituteand

B()=

B()=

B()=

)

Therefore ).


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