Solution Found!
The number of defects per yard Y for a certain fabric is
Chapter 5, Problem 42E(choose chapter or problem)
The number of defects per yard 𝑌 for a certain fabric is known to have a Poisson distribution
with parameter \(\lambda\). However, \(\lambda\) itself is a random variable with probability density function given by
\(f(\lambda)=\left\{\begin{array}{ll}
e^{-\lambda}, & \lambda \geq 0, \\
0, & \text { elsewhere. }
\end{array}\right.
\)
Find the unconditional probability function for 𝑌.
Equation Transcription:
Text Transcription:
lambda
lambda
f(lambda)={_0, elsewhere. ^e^-lambda, lambda>/=0,
Questions & Answers
QUESTION:
The number of defects per yard 𝑌 for a certain fabric is known to have a Poisson distribution
with parameter \(\lambda\). However, \(\lambda\) itself is a random variable with probability density function given by
\(f(\lambda)=\left\{\begin{array}{ll}
e^{-\lambda}, & \lambda \geq 0, \\
0, & \text { elsewhere. }
\end{array}\right.
\)
Find the unconditional probability function for 𝑌.
Equation Transcription:
Text Transcription:
lambda
lambda
f(lambda)={_0, elsewhere. ^e^-lambda, lambda>/=0,
ANSWER:
Solution:
Step 1 of 2:
The number of defects per yard Y for a certain fabric have a Poisson distribution with parameter . here
itself is a random variable with probability density function,
We have to find the unconditional probability function for Y.