Solved: In Exercise 5.16, Y1 and Y2 denoted the

Chapter 5, Problem 60E

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QUESTION:

In Exercise 5.16, \(Y_{1}\) and \(Y_{2}\) denoted the proportions of time that employees I and II actually spent working on their assigned tasks during a workday. The joint density of Y1 and Y2 is given by

                             \(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}

y_{1}+y_{2}, & 0 \leq y_{1} \leq 1,0 \leq y_{2} \leq 1, \\

0, & \text { elsewhere. }

\end{array}\right.

\)

Are \(Y_{1}\) and \(Y_{2}\) independent?

Equation Transcription:

Text Transcription:

Y_1

Y_2

Y_1

Y_2

f(y_1,y_2)={_0, elsewhere. ^y_1+y_2,  0</=y_1</=1,0</=y_2</=1,

Y_1

Y_2

Questions & Answers

QUESTION:

In Exercise 5.16, \(Y_{1}\) and \(Y_{2}\) denoted the proportions of time that employees I and II actually spent working on their assigned tasks during a workday. The joint density of Y1 and Y2 is given by

                             \(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}

y_{1}+y_{2}, & 0 \leq y_{1} \leq 1,0 \leq y_{2} \leq 1, \\

0, & \text { elsewhere. }

\end{array}\right.

\)

Are \(Y_{1}\) and \(Y_{2}\) independent?

Equation Transcription:

Text Transcription:

Y_1

Y_2

Y_1

Y_2

f(y_1,y_2)={_0, elsewhere. ^y_1+y_2,  0</=y_1</=1,0</=y_2</=1,

Y_1

Y_2

ANSWER:

Solution :

Step 1 of 1:

Let and have joint density function.

Then the joint density function and  is

Our goal is:

We need to find

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