Solution Found!
Solved: In Exercise 5.16, Y1 and Y2 denoted the
Chapter 5, Problem 60E(choose chapter or problem)
In Exercise 5.16, \(Y_{1}\) and \(Y_{2}\) denoted the proportions of time that employees I and II actually spent working on their assigned tasks during a workday. The joint density of Y1 and Y2 is given by
\(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}
y_{1}+y_{2}, & 0 \leq y_{1} \leq 1,0 \leq y_{2} \leq 1, \\
0, & \text { elsewhere. }
\end{array}\right.
\)
Are \(Y_{1}\) and \(Y_{2}\) independent?
Equation Transcription:
Text Transcription:
Y_1
Y_2
Y_1
Y_2
f(y_1,y_2)={_0, elsewhere. ^y_1+y_2, 0</=y_1</=1,0</=y_2</=1,
Y_1
Y_2
Questions & Answers
QUESTION:
In Exercise 5.16, \(Y_{1}\) and \(Y_{2}\) denoted the proportions of time that employees I and II actually spent working on their assigned tasks during a workday. The joint density of Y1 and Y2 is given by
\(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}
y_{1}+y_{2}, & 0 \leq y_{1} \leq 1,0 \leq y_{2} \leq 1, \\
0, & \text { elsewhere. }
\end{array}\right.
\)
Are \(Y_{1}\) and \(Y_{2}\) independent?
Equation Transcription:
Text Transcription:
Y_1
Y_2
Y_1
Y_2
f(y_1,y_2)={_0, elsewhere. ^y_1+y_2, 0</=y_1</=1,0</=y_2</=1,
Y_1
Y_2
ANSWER:
Solution :
Step 1 of 1:
Let and have joint density function.
Then the joint density function and is
Our goal is:
We need to find