Solution Found!
Suppose that, for ?1 ? ? ? 1, the probability density
Chapter 5, Problem 65E(choose chapter or problem)
Suppose that, for \(-1 \leq \alpha \leq 1\), the probability density function of \(\left(Y_1,\ Y_2\right)\) is given by
\(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}
{\left[1-\alpha\left\{\left(1-2 e^{-y_{1}}\right)\left(1-2 e^{-y_{2}}\right)\right\}\right] e^{-y_{1}-y_{2}},} & 0 \leq y_{1}, 0 \leq y_{2}, \\
0, & \text { elsewhere. }
\end{array}\right.
\)
a Show that the marginal distribution of \(Y_{1}\) is exponential with mean 1.
b What is the marginal distribution of \(Y_{2}\)?
c Show that \(Y_{1}\) and \(Y_{2}\) are independent if and only if \(\alpha=0\).
Notice that these results imply that there are infinitely many joint densities such that both marginals are exponential with mean 1.
Equation Transcription:
Text Transcription:
-1</=alpha</=1
(Y_1,Y_2)
f(y_1,y_2)={_0, elsewhere ^[1-alpha{(1-2e^-y_1)(1-2e^-y_2)}]e^-y_1-y_2, 0</=y1, 0</=y_2.
Y_1
Y_2
Y_1
Y_2
alpha=0
Questions & Answers
QUESTION:
Suppose that, for \(-1 \leq \alpha \leq 1\), the probability density function of \(\left(Y_1,\ Y_2\right)\) is given by
\(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}
{\left[1-\alpha\left\{\left(1-2 e^{-y_{1}}\right)\left(1-2 e^{-y_{2}}\right)\right\}\right] e^{-y_{1}-y_{2}},} & 0 \leq y_{1}, 0 \leq y_{2}, \\
0, & \text { elsewhere. }
\end{array}\right.
\)
a Show that the marginal distribution of \(Y_{1}\) is exponential with mean 1.
b What is the marginal distribution of \(Y_{2}\)?
c Show that \(Y_{1}\) and \(Y_{2}\) are independent if and only if \(\alpha=0\).
Notice that these results imply that there are infinitely many joint densities such that both marginals are exponential with mean 1.
Equation Transcription:
Text Transcription:
-1</=alpha</=1
(Y_1,Y_2)
f(y_1,y_2)={_0, elsewhere ^[1-alpha{(1-2e^-y_1)(1-2e^-y_2)}]e^-y_1-y_2, 0</=y1, 0</=y_2.
Y_1
Y_2
Y_1
Y_2
alpha=0
ANSWER:
Solution
Step 1 of 3
a) We have to show that the marginal distribution of Y1 is exponential with mean 1
Given that
= 0, Otherwise
The marginal distribution function of Y1 is
=
=
The function which we got is exponential distribution with
Hence the marginal distribution of Y1 is exponential with mean 1