Answer: In Exercise 5.18, Y1 and Y2 denoted the lengths of

Chapter 5, Problem 81E

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QUESTION:

In Exercise 5.18, \(Y_{1}\) and \(Y_{2}\) denoted the lengths of life, in hundreds of hours, for components of types I and II, respectively, in an electronic system. The joint density of \(Y_{1}\) and \(Y_{2}\) is

                               \(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}

(1 / 8) y_{1} e^{-\left(y_{1}+y_{2}\right) / 2}, & y_{1}>0, y_{2}>0, \\

0, & \text { elsewhere. }

\end{array}\right.

\)

One way to measure the relative efficiency of the two components is to compute the ratio \(Y_{2} / Y_{1}\). Find \(E\left(Y_{2} / Y_{1}\right)\). [Hint: In Exercise 5.61, we proved that \(Y_{1}\) and \(Y_{2}\) are independent.]

Equation Transcription:

Text Transcription:

Y_1

Y_2

Y_1

Y_2

f(y_1,y_2)={_0,       elsewhere. ^(1/8)y_1e^-(y_1+y_2)/2, y_1>0,y_2>0,

Y_2/Y_1

E(Y_2/Y_1)

Y_1

Y_2

Questions & Answers

QUESTION:

In Exercise 5.18, \(Y_{1}\) and \(Y_{2}\) denoted the lengths of life, in hundreds of hours, for components of types I and II, respectively, in an electronic system. The joint density of \(Y_{1}\) and \(Y_{2}\) is

                               \(f\left(y_{1}, y_{2}\right)=\left\{\begin{array}{ll}

(1 / 8) y_{1} e^{-\left(y_{1}+y_{2}\right) / 2}, & y_{1}>0, y_{2}>0, \\

0, & \text { elsewhere. }

\end{array}\right.

\)

One way to measure the relative efficiency of the two components is to compute the ratio \(Y_{2} / Y_{1}\). Find \(E\left(Y_{2} / Y_{1}\right)\). [Hint: In Exercise 5.61, we proved that \(Y_{1}\) and \(Y_{2}\) are independent.]

Equation Transcription:

Text Transcription:

Y_1

Y_2

Y_1

Y_2

f(y_1,y_2)={_0,       elsewhere. ^(1/8)y_1e^-(y_1+y_2)/2, y_1>0,y_2>0,

Y_2/Y_1

E(Y_2/Y_1)

Y_1

Y_2

ANSWER:

Answer:

Step 1 of 1:

In Exercise   and  denoted the lengths of life, in hundreds of hours, for components of types  respectively, in an electronic system.

The joint probability density function of  and  is given by,

One way to measure the relative efficiency of the two components is to compute the ratio

We need to find the value of

The marginal density functions of  and  respectively, are given by

Hence the marginal density functions for  is,

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