Solution: In Exercise 5.3, we determined that the joint

Chapter 5, Problem 90E

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QUESTION:

In Exercise 5.3, we determined that the joint probability distribution of  \(Y_{1}\) the number of married executives, and \(Y_{2}\), the number of never-married executives, is given by

                               \(p\left(y_{1,} y_{2}\right)=\frac{\left(\begin{array}{l}4 \\y_{1}\end{array}\right)\left(\begin{array}{l}3 \\y_{2}\end{array}\right)\left(\begin{array}{l}2 \\3-y_{1}=y_{2}\end{array}\right)}{\left({}_{3}^{9}\right)}\)

where \(y_{1}\) and \(y_{2}\) are integers, \(0 \leq y_{1} \leq 3,0 \leq y_{2} \leq 3\), and \(1 \leq y_{1}+y_{2} \leq 3\). Find \(\operatorname{Cov}\left(Y_{1}, Y_{2}\right)\).

Equation Transcription:

       

+

Text Transcription:

Y_1

Y_2

p(y_1,y_2)=(y_1 ^4)(y_ 2 ^3)(3-y_1=y_2 ^2)/_3 ^9

y_1

y_2

0 leq y_1 leq 3,0 leq y_2 leq 3      

1 leq y_1+y_2 leq 3

Cov(Y_1,Y_2)

Questions & Answers

QUESTION:

In Exercise 5.3, we determined that the joint probability distribution of  \(Y_{1}\) the number of married executives, and \(Y_{2}\), the number of never-married executives, is given by

                               \(p\left(y_{1,} y_{2}\right)=\frac{\left(\begin{array}{l}4 \\y_{1}\end{array}\right)\left(\begin{array}{l}3 \\y_{2}\end{array}\right)\left(\begin{array}{l}2 \\3-y_{1}=y_{2}\end{array}\right)}{\left({}_{3}^{9}\right)}\)

where \(y_{1}\) and \(y_{2}\) are integers, \(0 \leq y_{1} \leq 3,0 \leq y_{2} \leq 3\), and \(1 \leq y_{1}+y_{2} \leq 3\). Find \(\operatorname{Cov}\left(Y_{1}, Y_{2}\right)\).

Equation Transcription:

       

+

Text Transcription:

Y_1

Y_2

p(y_1,y_2)=(y_1 ^4)(y_ 2 ^3)(3-y_1=y_2 ^2)/_3 ^9

y_1

y_2

0 leq y_1 leq 3,0 leq y_2 leq 3      

1 leq y_1+y_2 leq 3

Cov(Y_1,Y_2)

ANSWER:

Solution:

Step 1 of 3:

It is given that in a firm there are 9 executives out of which 4 are married,3 are unmarried and 2 are divorced.

denotes the number of married executives and denotes the number of unmarried executes.

Also, it is given that 3 executives are selected at random for promotion.

The joint probability distribution of and is given as

P(,)=,0

Using this we need to find the Cov(,).


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