Actinomycin D's Impact on RNA Synthesis: An Experimental Insigh

Chapter 10, Problem 52E

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QUESTION:

A biologist has hypothesized that high concentrations of actinomycin D inhibit RNA synthesis in cells and thereby inhibit the production of proteins. An experiment conducted to test this theory compared the RNA synthesis in cells treated with two concentrations of actinomycin D: 0.6 and 0.7 micrograms per liter. Cells treated with the lower concentration (0.6) of actinomycin D yielded that 55 out of 70 developed normally whereas only 23 out of 70 appeared to develop normally for the higher concentration (0.7). Do these data indicate that the rate of normal RNA synthesis is lower for cells exposed to the higher concentrations of actinomycin D?

a. Find the p-value for the test.

b. If you chose to use \(\alpha=.05\) what is your conclusion?

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Actinomycin D's Impact on RNA Synthesis: An Experimental Insigh
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Explore a biologist's experiment testing the effects of actinomycin D concentrations on RNA synthesis in cells. By analyzing the outcomes and calculating p-values, this video offers insights into how higher concentrations might inhibit normal RNA synthesis.

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Questions & Answers

QUESTION:

A biologist has hypothesized that high concentrations of actinomycin D inhibit RNA synthesis in cells and thereby inhibit the production of proteins. An experiment conducted to test this theory compared the RNA synthesis in cells treated with two concentrations of actinomycin D: 0.6 and 0.7 micrograms per liter. Cells treated with the lower concentration (0.6) of actinomycin D yielded that 55 out of 70 developed normally whereas only 23 out of 70 appeared to develop normally for the higher concentration (0.7). Do these data indicate that the rate of normal RNA synthesis is lower for cells exposed to the higher concentrations of actinomycin D?

a. Find the p-value for the test.

b. If you chose to use \(\alpha=.05\) what is your conclusion?

ANSWER:

Step 1 of 3

a) The available information is as shown below:

\(\begin{array}{|l|l|} \hline x_{1}=55 & n_{1}=70 \\ \hline x_{2}=23 & n_{2}=70 \\ \hline \end{array} \)

Let \(\mathrm{p}_{1}\) and \(\mathrm{p}_{2}\) denote the rate of normal RNA synthesis for cells exposed to lower concentration (0.6) and higher concentration (0.7), respectively.

Calculate the sample proportions values as,

\(\begin{aligned} p_{1} & =\frac{x_{1}}{n_{1}} \\ & =55 / 70 \\ & =0.79 \end{aligned}\)

\(\begin{aligned} p_{2} & =\frac{x_{2}}{n_{2}} \\ & =23 / 70 \\ & =0.33 \end{aligned}\)

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