Problem 30.81
A 20 cm * 20 cm square loop has a resistance of 0.10 . A magnetic field perpendicular to the loop is B = 4t - 2t 2 , where B is in tesla and t is in seconds. What is the current in the loop at t = 0.0 s, t = 1.0 s, and t = 2.0 s?
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Chapter 4 Two and Three Dimensional Motion The best way to work with multidimensional vectors is by using component form The position is written as:r=xi+yj+zk In this case x, y, and z would represent constants Displacement is shown as: ∆ r=∆ xi+∆ yj+∆zk Average Velocity: v= ∆r ∆ t If needed break this up into component for and do the final minus the initial positon and divide it by time. Think of it as being the slope for the position (rise over run). Instantaneous Velocity: v= dr dt Acceleration: a= ∆v
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Chapter 30, Problem 30.81 is Solved
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