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A 20 cm * 20 cm square loop has a resistance of 0.10 . A

Physics for Scientists and Engineers: A Strategic Approach, Standard Edition (Chs 1-36) | 4th Edition | ISBN: 9780134081496 | Authors: Randall D. Knight (Professor Emeritus) ISBN: 9780134081496 191

Solution for problem 30.81 Chapter 30

Physics for Scientists and Engineers: A Strategic Approach, Standard Edition (Chs 1-36) | 4th Edition

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Physics for Scientists and Engineers: A Strategic Approach, Standard Edition (Chs 1-36) | 4th Edition | ISBN: 9780134081496 | Authors: Randall D. Knight (Professor Emeritus)

Physics for Scientists and Engineers: A Strategic Approach, Standard Edition (Chs 1-36) | 4th Edition

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Problem 30.81

A 20 cm * 20 cm square loop has a resistance of 0.10 . A magnetic field perpendicular to the loop is B = 4t - 2t 2 , where B is in tesla and t is in seconds. What is the current in the loop at t = 0.0 s, t = 1.0 s, and t = 2.0 s?

Step-by-Step Solution:
Step 1 of 3

Chapter 4 Two and Three Dimensional Motion The best way to work with multidimensional vectors is by using component form The position is written as:r=xi+yj+zk In this case x, y, and z would represent constants Displacement is shown as: ∆ r=∆ xi+∆ yj+∆zk Average Velocity: v= ∆r ∆ t If needed break this up into component for and do the final minus the initial positon and divide it by time. Think of it as being the slope for the position (rise over run). Instantaneous Velocity: v= dr dt Acceleration: a= ∆v

Step 2 of 3

Chapter 30, Problem 30.81 is Solved
Step 3 of 3

Textbook: Physics for Scientists and Engineers: A Strategic Approach, Standard Edition (Chs 1-36)
Edition: 4
Author: Randall D. Knight (Professor Emeritus)
ISBN: 9780134081496

The full step-by-step solution to problem: 30.81 from chapter: 30 was answered by , our top Physics solution expert on 12/28/17, 08:06PM. Since the solution to 30.81 from 30 chapter was answered, more than 547 students have viewed the full step-by-step answer. This full solution covers the following key subjects: . This expansive textbook survival guide covers 42 chapters, and 4463 solutions. The answer to “A 20 cm * 20 cm square loop has a resistance of 0.10 . A magnetic field perpendicular to the loop is B = 4t - 2t 2 , where B is in tesla and t is in seconds. What is the current in the loop at t = 0.0 s, t = 1.0 s, and t = 2.0 s?” is broken down into a number of easy to follow steps, and 60 words. This textbook survival guide was created for the textbook: Physics for Scientists and Engineers: A Strategic Approach, Standard Edition (Chs 1-36), edition: 4. Physics for Scientists and Engineers: A Strategic Approach, Standard Edition (Chs 1-36) was written by and is associated to the ISBN: 9780134081496.

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A 20 cm * 20 cm square loop has a resistance of 0.10 . A