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(II) An oil drop whose mass is 2.8 x 10-15 Kg is held at
Chapter 8, Problem 3P(choose chapter or problem)
(II) An oil drop whose mass is determined to be \(2.8 \times 10^{-15} \mathrm{~kg}\)is held at rest between two large plates separated by 1.0 cm when the potential difference between them is . How many excess electrons does this drop have?
Equation Transcription:
Text Transcription:
2.8 x 10^-15kg
Questions & Answers
QUESTION:
(II) An oil drop whose mass is determined to be \(2.8 \times 10^{-15} \mathrm{~kg}\)is held at rest between two large plates separated by 1.0 cm when the potential difference between them is . How many excess electrons does this drop have?
Equation Transcription:
Text Transcription:
2.8 x 10^-15kg
ANSWER:
Solution 3P: We have to calculate the number of electron possessed by an oil drop in Millikan’s oil drop experiment owing to which it remain suspended in between the air. Step 1 of 3 Concept: Weight of the oil drop is Fg= mg is directed directly downwards due to Earth’s gravitational force. Electric force acting on the charged oil drop is Fe= qE which is directed in the vertically upward direction. Here, q Charge on the oil drop E Electric field between the plates Electric field between the two parallel plates separated by the distance d when a potential difference of V is applied across it ends, is given as, E = V d