Solution Found!
Suppose that 8% of college students are vegetarians.
Chapter , Problem 6.1(choose chapter or problem)
Suppose that 8% of college students are vegetarians. Determine if the following statements are true or false, and explain your reasoning.
(a) The distribution of the sample proportions of vegetarians in random samples of size 60 is approximately normal since \(n \geq 30\).
(b) The distribution of the sample proportions of vegetarian college students in random samples of size 50 is right skewed.
(c) A random sample of 125 college students where 12% are vegetarians would be considered unusual.
(d) A random sample of 250 college students where 12% are vegetarians would be considered unusual.
(e) The standard error would be reduced by one-half if we increased the sample size from 125 to 250
Questions & Answers
QUESTION:
Suppose that 8% of college students are vegetarians. Determine if the following statements are true or false, and explain your reasoning.
(a) The distribution of the sample proportions of vegetarians in random samples of size 60 is approximately normal since \(n \geq 30\).
(b) The distribution of the sample proportions of vegetarian college students in random samples of size 50 is right skewed.
(c) A random sample of 125 college students where 12% are vegetarians would be considered unusual.
(d) A random sample of 250 college students where 12% are vegetarians would be considered unusual.
(e) The standard error would be reduced by one-half if we increased the sample size from 125 to 250
ANSWER:
Step 1 of 5
(a) The statement is False.
In the success-failure condition we expected to see at least 10 successes and 10 failures in our sample, i.e. \(n p \geq 10 \text { and } n(1-p) \geq 10\).
Population proportion, \(p=8%=0.08\) (Given)
sample of size, \(n=60\) (Given)
Then, \(np=60(0.08)=4.8\)
So, \(np < 10\), this statement doesn’t satisfy the success-failure condition.