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Answer: A 46.2-mL, 0.568 M calcium nitrate [Ca(NO3)2]

Chapter 4, Problem 4.78

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QUESTION:

A 46.2-mL, 0.568 M calcium nitrate [Ca(NO3)2] solution is mixed with 80.5 mL of 1.396 M calcium nitrate solution. Calculate the concentration of the final solution.

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QUESTION:

A 46.2-mL, 0.568 M calcium nitrate [Ca(NO3)2] solution is mixed with 80.5 mL of 1.396 M calcium nitrate solution. Calculate the concentration of the final solution.

ANSWER:

Step 1 of 4

From the given,

Molarity = 0.568M

Volume = 46.2 mL

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