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Answer: A 22.02-mL solution containing 1.615 g Mg(NO3)2 is

Chemistry | 12th Edition | ISBN: 9780078021510 | Authors: Raymond Chang; Kenneth Goldsby ISBN: 9780078021510 98

Solution for problem 4.165 Chapter 4

Chemistry | 12th Edition

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Chemistry | 12th Edition | ISBN: 9780078021510 | Authors: Raymond Chang; Kenneth Goldsby

Chemistry | 12th Edition

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Problem 4.165

A 22.02-mL solution containing 1.615 g Mg(NO3)2 is mixed with a 28.64-mL solution containing 1.073 g NaOH. Calculate the concentrations of the ions remaining in solution after the reaction is complete. Assume volumes are additive

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Chem 111 ­ Introductory Chemistry I University of Massachusetts, Amherst Professor Surampudi Lecture 2 Best way to contact Professor­ send message through moodle Slides on Moodle before class Chapter 1: Matter on the Atomic Scale ● Key Idea: Properties of matter depends on the types and arrangement of the atoms and molecules Balloon Experiment

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Chapter 4, Problem 4.165 is Solved
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Textbook: Chemistry
Edition: 12
Author: Raymond Chang; Kenneth Goldsby
ISBN: 9780078021510

This textbook survival guide was created for the textbook: Chemistry, edition: 12. Chemistry was written by and is associated to the ISBN: 9780078021510. The answer to “A 22.02-mL solution containing 1.615 g Mg(NO3)2 is mixed with a 28.64-mL solution containing 1.073 g NaOH. Calculate the concentrations of the ions remaining in solution after the reaction is complete. Assume volumes are additive” is broken down into a number of easy to follow steps, and 35 words. The full step-by-step solution to problem: 4.165 from chapter: 4 was answered by , our top Chemistry solution expert on 09/09/17, 04:35AM. This full solution covers the following key subjects: . This expansive textbook survival guide covers 25 chapters, and 3241 solutions. Since the solution to 4.165 from 4 chapter was answered, more than 316 students have viewed the full step-by-step answer.

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Answer: A 22.02-mL solution containing 1.615 g Mg(NO3)2 is