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Solved: Ethanol (C2H5OH) burns in air: C2H5OH(l) 1 O2(g)
Chapter 5, Problem 5.62(choose chapter or problem)
Ethanol (C2H5OH) burns in air: C2H5OH(l) 1 O2(g) CO2(g) 1 H2O(l) Balance the equation and determine the volume of air in liters at 35.0C and 790 mmHg required to burn 227 g of ethanol. Assume that air is 21.0 percent O2 by volume
Questions & Answers
QUESTION:
Ethanol (C2H5OH) burns in air: C2H5OH(l) 1 O2(g) CO2(g) 1 H2O(l) Balance the equation and determine the volume of air in liters at 35.0C and 790 mmHg required to burn 227 g of ethanol. Assume that air is 21.0 percent O2 by volume
ANSWER:Step 1 of 6
According to ideal gas law, the number of moles can be calculated by the following formula.
........................(1)
P = pressure
V = Volume
n = Number of moles
R = Gas constant
T = Temperature.
Let’s calculate the number of moles;
.........................(2)