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Solved: Ethanol (C2H5OH) burns in air: C2H5OH(l) 1 O2(g)

Chapter 5, Problem 5.62

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QUESTION:

Ethanol (C2H5OH) burns in air: C2H5OH(l) 1 O2(g) CO2(g) 1 H2O(l) Balance the equation and determine the volume of air in liters at 35.0C and 790 mmHg required to burn 227 g of ethanol. Assume that air is 21.0 percent O2 by volume

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QUESTION:

Ethanol (C2H5OH) burns in air: C2H5OH(l) 1 O2(g) CO2(g) 1 H2O(l) Balance the equation and determine the volume of air in liters at 35.0C and 790 mmHg required to burn 227 g of ethanol. Assume that air is 21.0 percent O2 by volume

ANSWER:

Step 1 of 6

According to ideal gas law, the number of moles can be calculated by the following formula.

                                                  ........................(1)

                                                     

P = pressure

V = Volume

n = Number of moles

R = Gas constant

T = Temperature.

Let’s calculate the number of moles;

                                                          .........................(2)

 

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