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Solution: The standard enthalpies of formation of ions in

Chemistry | 12th Edition | ISBN: 9780078021510 | Authors: Raymond Chang; Kenneth Goldsby ISBN: 9780078021510 98

Solution for problem 6.52 Chapter 6

Chemistry | 12th Edition

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Chemistry | 12th Edition | ISBN: 9780078021510 | Authors: Raymond Chang; Kenneth Goldsby

Chemistry | 12th Edition

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Problem 6.52

The standard enthalpies of formation of ions in aqueous solutions are obtained by arbitrarily assigning a value of zero to H1 ions; that is, Hf[H1 (aq)] 5 0. (a) For the following reaction HCl(g) H2O H1(aq) 1 Cl2(aq) H 5 274.9 kJ/mol calculate DH8f for the Cl2 ions. (b) Given that DH8f for OH2 ions is 2229.6 kJ/mol, calculate the enthalpy of neutralization when 1 mole of a strong monoprotic acid (such as HCl) is titrated by 1 mole of a strong base (such as KOH) at 258C.

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CHATER 11 ^IMF=^MP, ^BP, ^Viscosity, ^Surface Tension, vVP [S]Ion-D, H-Bond, D-D, Dis[W] vIMF=vMP, vBP, vViscosity, vSurface Tension, ^VP IMF, MM, Surface Tension= order of Prop. Ln(p2/p1)=(-DeltaH/R)(1/T2 – 1/T1) R=8.314 J/k.mol Q=n.DeltaH [no change in heat] Q=m.Cs.DeltaT T=C 1D=3.34e-30 C.m [S.D]S, L, G. [H-Bond]ration of 1 to 1 of lone pair and H, the more pairs the more higher/stronger. [G]Deposition[S]-DeltaH [S]Sublimation[G]+DeltaH [S]Melting[L]+DeltaH [L]Vaporization[G]+DeltaH [G]Condensation[L]-DeltaH [L]Freezing[S]-DeltaH DeltaH=KJ/mol DeltaHsub=DeltaHfus + DeltaHvap Equal VP= Evap and Conden even [Closed System] Normal Boiling Point= 1atm 1atm= 1/760torr (760torr) =760mmHg In(Pvap)=(-DeltaH/R)(1/T)+lnB Y=MX+B C+273.15K=K When given KJ use DeltaH to get mo

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Chapter 6, Problem 6.52 is Solved
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Textbook: Chemistry
Edition: 12
Author: Raymond Chang; Kenneth Goldsby
ISBN: 9780078021510

Chemistry was written by and is associated to the ISBN: 9780078021510. The full step-by-step solution to problem: 6.52 from chapter: 6 was answered by , our top Chemistry solution expert on 09/09/17, 04:35AM. This textbook survival guide was created for the textbook: Chemistry, edition: 12. The answer to “The standard enthalpies of formation of ions in aqueous solutions are obtained by arbitrarily assigning a value of zero to H1 ions; that is, Hf[H1 (aq)] 5 0. (a) For the following reaction HCl(g) H2O H1(aq) 1 Cl2(aq) H 5 274.9 kJ/mol calculate DH8f for the Cl2 ions. (b) Given that DH8f for OH2 ions is 2229.6 kJ/mol, calculate the enthalpy of neutralization when 1 mole of a strong monoprotic acid (such as HCl) is titrated by 1 mole of a strong base (such as KOH) at 258C.” is broken down into a number of easy to follow steps, and 88 words. Since the solution to 6.52 from 6 chapter was answered, more than 370 students have viewed the full step-by-step answer. This full solution covers the following key subjects: . This expansive textbook survival guide covers 25 chapters, and 3241 solutions.

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Solution: The standard enthalpies of formation of ions in