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Solution: The thermal decomposition of phosphine (PH3) into

Chemistry | 12th Edition | ISBN: 9780078021510 | Authors: Raymond Chang; Kenneth Goldsby ISBN: 9780078021510 98

Solution for problem 12.26 Chapter 13

Chemistry | 12th Edition

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Chemistry | 12th Edition | ISBN: 9780078021510 | Authors: Raymond Chang; Kenneth Goldsby

Chemistry | 12th Edition

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Problem 12.26

The thermal decomposition of phosphine (PH3) into phosphorus and molecular hydrogen is a first-order reaction: 4PH3(g) P4(g) 1 6H2(g) The half-life of the reaction is 35.0 s at 6808C. Calculate (a) the first-order rate constant for the reaction and (b) the time required for 95 percent of the phosphine to decompose.

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CH. 1: MATTER AND ENERGY 1.1: States of Matter Matter: ​object that has mass (m) and occupies space Chemistry: ​study of the composition, structure, and properties of matter Solid→ definite volume and shape ● May vibrate ● Compact ● Stationary ● Can’t move past other molecules Liquid→ definite volume, but​ OT​ a definite shape ● Can flow past each other Gas (vapor) → ​NO​ definite volume and ​NO​ definite shape ● Separated ● Mostly empty space ❖ Matter can be transformed from one physical state to another as its temp goes up or down Atom: ​smallest particle of an element Molecules: ​2+ atoms of same element Ex) H2 Chemical bonds: ​force that holds 2 atoms in a molecule or compound together Melting: solid→ liquid Ex) Ice tur

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Chapter 13, Problem 12.26 is Solved
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Textbook: Chemistry
Edition: 12
Author: Raymond Chang; Kenneth Goldsby
ISBN: 9780078021510

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Solution: The thermal decomposition of phosphine (PH3) into