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# Solved: (I) If ? particles are accelerated by the

ISBN: 9780130606204 3

## Solution for problem 3P Chapter 32

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition

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Problem 3P

(I) What strength of magnetic field is used in a cyclotron in which protons make  revolutions per second?

Step-by-Step Solution:

Step-by-step solution Step 1 of 1 The frequency of rotation f = 2.6 x 10 rev/s. 7 If B be the strength of the magnetic field, then the radius of the circle, traveled by the proton is: 2f = Be/m, where m is the mass of the proton. Therefore, B = 2fm/e = {2 x 3.14 x (2.6 x 10 ) x (1.66 x 10 )} / 1.6 x 10 -27 -19T = 1.69 T = required magnitude of the magnetic field.

Step 2 of 1

##### ISBN: 9780130606204

This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. The answer to “?(I) What strength of magnetic field is used in a cyclotron in which protons make revolutions per second?” is broken down into a number of easy to follow steps, and 18 words. This full solution covers the following key subjects: accelerated, applied, cyclotron, dees, Example. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. The full step-by-step solution to problem: 3P from chapter: 32 was answered by , our top Physics solution expert on 03/03/17, 03:53PM. Since the solution to 3P from 32 chapter was answered, more than 413 students have viewed the full step-by-step answer.

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Solved: (I) If ? particles are accelerated by the