A sequential circuit contains two D flip-flops; the
Chapter 15, Problem 15.38(choose chapter or problem)
A sequential circuit contains two D flip-flops; the excitation equations for the flip-flops are \(D_1=X Q_1+X Q_2\) and \(D_2=X Q_1+X Q_2^{\prime}\).
(a) Convert the circuit into an equivalent one where each D flip-flop is replaced by a T flip-flop. Do this by converting the next-state equations into the form for a T flip-flop. (Hint: \(M Q+N Q^{\prime}=\left(M^{\prime} Q+N Q^{\prime}\right)^{\prime} Q+\left(M^{\prime} Q+N Q^{\prime}\right) Q^{\prime}\).)
(b) Repeat part (a) by constructing an excitation table for the T flip-flops (i.e., a truth table for \(T_1\) and \(T_2\) as a function of \(X, Q_1\), and \(Q_2\) ).
(c) Convert the circuit into an equivalent one where each D flip-flop is replaced by a J-K flip-flop. Do this by converting the next-state equations into the form for a J-K flip-flop.
(d) Repeat part (c) by constructing an excitation table for the J-K flip-flops (i.e., a truth table for the J-K flip-flop inputs as a function of \(X, Q_1\), and \(Q_2\) ).
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