As mentioned in the chapter opener, the golden mean, F ,
Chapter , Problem 1.4.83(choose chapter or problem)
As mentioned in the chapter opener, the golden mean, F , occurs in many situations. The exact value of F is 1 152. Exercises 82 and 83 involve the golden mean. Here is a method of constructing a golden rectangle, a rectanglein which the ratio of the length to the width is . Begin with a square whose sides are 2 units. (You can use any length.) Fromthe midpoint of one side, draw a line segment to an opposite vertex. Using a compass, create an arc that intersects an extensionof the base of the square. Now complete the rectangle.(See the following diagram.) Show that ADAB = f. A EF 1 1B
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