In Exercises 69 to 72, show that (gf)(x) = x and (gf )(x) = x. f(x) = 4x + 1, g(x) = 4 - xx
Step 1 of 3
Intro to Applied Stats: Chapter 8 Objectives: ● Describe the mean and median both verbally and algebraically ○ Mean, verbally: average of all scores in a distribution. Mean, algebraically: X bar = ΣX/n. So, X bar = X + X 1X .2/N. 3bar is the mean, N is the number of scores, Σ is the verb directing us to sum the measures, X etc. is th1individual scores. ○ Median, verbally: score in a distribution of scores, above and below which one-half of the frequencies fall. Median, algebraically: MDN locationN+1/ 2. Median for group frequencies: MDN = X + (i)(N/2 - iif )/ f ll i ● Discu
Textbook: College Algebra
Author: Richard N. Aufmann, Vernon C. Barker, Richard D. Nation
This full solution covers the following key subjects: . This expansive textbook survival guide covers 9 chapters, and 4425 solutions. Since the solution to 2.6.71 from 2 chapter was answered, more than 231 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 2.6.71 from chapter: 2 was answered by , our top Math solution expert on 01/02/18, 08:47PM. This textbook survival guide was created for the textbook: College Algebra, edition: 7. The answer to “In Exercises 69 to 72, show that (gf)(x) = x and (gf )(x) = x. f(x) = 4x + 1, g(x) = 4 - xx” is broken down into a number of easy to follow steps, and 25 words. College Algebra was written by and is associated to the ISBN: 9781439048610.