dw dt = (3 w)(w + 1), w(0) = 4, 0 t 5, t = 1.0

L8 - 10 Now You Try It (NYTI): 1. Evaluate the limits, if possible. 1 − 1 x x − 12 (a) lim x→4 x − 4 √ √ x +2 − 2 (b) x→0 x 4 − x (c) li+ x→3 ln(x − 3) (d) lim ln(x − 3) x→3+ 4 − x 2. Evaluate the limits below involving absolute values, if possible. 2 x − 2|x| (a)x→0mx − 4x x − 4x +3 (b) lim x→3 |3 − x|