Simplify each of the following. 2 sin 15 cos 15

L8 - 2 Note the following (Theorem 1, Section 2.2): 6. x→c k = 7. lim x = x→c ex. Evaluate lim (2x +3 x − 2). x→−1 2 Note that x→−1f(x)= m lx→−1(2x +3x−2) = f(−1). That is, we can ﬁnd the limit by direct substitution. Direct Substitution Property If f(x)iaolmild c is in the domain of f then x→cm f(x)=