Find all radian solutions using exact values only.sin x + cos x = 0
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March 2125, 2016 Section 3.2 Suppose f’(x) >0 for all x on an open interval I. Suppose x < x i1 I. 2 en f(x) is continuous on [x1 x2] and it is differentiable on (x 1 x 2 2 x ¿ So by Mean Value Theorem there is c ¿ f( )1f ¿ ' ϵ ( 1x S2)hthen f (c)=¿ Which implies Thus f(x)< 0 is increasing on I. By similar arguments, we can show that f’(x)< 0 on an open interval f is decreasing on I. And if f’(x)=0 on an open interval I, then f(x) is constant on I. Theorem If f’(x)=
Author: Charles P McKeague
This textbook survival guide was created for the textbook: Trigonometry, edition: . The full step-by-step solution to problem: 7.1.87 from chapter: 7.2 was answered by , our top Math solution expert on 01/02/18, 08:55PM. Trigonometry was written by and is associated to the ISBN: 9780495108351. This full solution covers the following key subjects: . This expansive textbook survival guide covers 58 chapters, and 3545 solutions. Since the solution to 7.1.87 from 7.2 chapter was answered, more than 251 students have viewed the full step-by-step answer. The answer to “Find all radian solutions using exact values only.sin x + cos x = 0” is broken down into a number of easy to follow steps, and 14 words.