Solution Found!
Using Specific Volume, Volume, and PressureReferring to
Chapter 1, Problem 32P(choose chapter or problem)
Referring to Fig. 1.7,
(a) if the pressure in the tank is 1.5 bar and atmospheric pressure is 1 bar, determine L, in m, for water with a density of \(997 \mathrm{~kg} / \mathrm{m}^3\) as the manometer liquid. Let \(g=9.81 \mathrm{~m} / \mathrm{s}^2\).
(b) determine L, in cm, if the manometer liquid is mercury with a density of \(13.59 \mathrm{~g} / \mathrm{cm}^3\) and the gas pressure is 1.3 bar. A barometer indicates the local atmospheric pressure is \(750 \mathrm{mmHg}\). Let \(g=9.81 \mathrm{~m} / \mathrm{s}^2\).
Questions & Answers
QUESTION:
Referring to Fig. 1.7,
(a) if the pressure in the tank is 1.5 bar and atmospheric pressure is 1 bar, determine L, in m, for water with a density of \(997 \mathrm{~kg} / \mathrm{m}^3\) as the manometer liquid. Let \(g=9.81 \mathrm{~m} / \mathrm{s}^2\).
(b) determine L, in cm, if the manometer liquid is mercury with a density of \(13.59 \mathrm{~g} / \mathrm{cm}^3\) and the gas pressure is 1.3 bar. A barometer indicates the local atmospheric pressure is \(750 \mathrm{mmHg}\). Let \(g=9.81 \mathrm{~m} / \mathrm{s}^2\).
ANSWER:Part (a)
Step 1 of 5:
Consider a tank filled with a gas at a particular pressure in bar scale. The manometer is connected to the tank to measure its pressure. The local atmospheric pressure is also given. We are going to find the level of the water column in the manometer.
The pressure in the tank P = 1.5 bar = 1.5 x 105 Pa
The atmospheric pressure Pa = 1 bar = 105 Pa
The density of water ρ = 997 kg/m3
The acceleration due to gravity g = 9.81 m/s2