A 0.060-g handball is thrown straight toward a wall with a

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QUESTION:

A 0.060-g handball is thrown straight toward a wall with a speed of It rebounds straight backward at a speed of (a) What impulse is exerted on the wall? (b) If the ball is in contact with the wall for what average force is exerted on the wall by the ball? (c) The rebounding ball is caught by a player who brings it to rest. In the process, her hand moves back What is the impulse received by the player? (d) What average force was exerted on the player by the ball?

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QUESTION:

A 0.060-g handball is thrown straight toward a wall with a speed of It rebounds straight backward at a speed of (a) What impulse is exerted on the wall? (b) If the ball is in contact with the wall for what average force is exerted on the wall by the ball? (c) The rebounding ball is caught by a player who brings it to rest. In the process, her hand moves back What is the impulse received by the player? (d) What average force was exerted on the player by the ball?

ANSWER:

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The average force exerted on the wall by the hand ball can be calculated by dividing the change in the momentum of the ball with the contact time of the ball with the wall. The impulse received by the player is the change in the momentum of the ball during the collision. The average force exerted on the player by the ball can be calculated by considering the change in the momentum of the ball and contact time of the ball with the player.

We have the values

Mass of the hand ball,

Initial speed of the ball in the  direction,

Final speed of the ball after the collision in  direction,

Contact time of the ball with the wall,

Velocity of the ball after caught by the player,

Distance that hand moves back,

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