A1.00-kg block (mass m) and a second block (mass M) are both initially at rest on a frictionless inclined plane (Figure 8-56). Mass M rests against a spring that has a force constant of The distance along the plane between the two blocks is The 1.00-kg block is released, making an elastic collision with the larger block. The 1.00-kg block then rebounds a distance of back up the inclined plane. The block of mass M momentarily comes to rest from its initial position. Find M. SSM
Thursday, October 6, 2016 7 Ideas F = m a How far will the car go in 4 sec M = 2 slugs , F = 50 1) a = f/m _______________________ Chapter 15: Circular Motion *3 Ways to Accelerate 1) Make an object move faster 2) Make an object more slower 3) Make a moving object change direction by going around a curve *Centripetal Force:- a real force that pushes inward. (where the tires push the car while steering) *Centrifugal Reaction:- a false force that pushed outward. (reaction) 1