Using Entropy Data and ConceptsPropane undergoes a process

Chapter 6, Problem 10P

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QUESTION:

Propane undergoes a process from state 1, where \(p_{1}=1.4\) MPa, \(T_{1}=60^{\circ} \mathrm{C}\), to state 2, where \(p_{2}=1.0\) MPa, during which the change in specific entropy is \(s_{2}-s_{1}=-0.035 \mathrm{\ kJ} / \mathrm{kg} \cdot \mathrm{K}\). At state 2, determine the temperature, in \({ }^{\circ} \mathrm{C}\), and the specific enthalpy, in kJ/kg.

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QUESTION:

Propane undergoes a process from state 1, where \(p_{1}=1.4\) MPa, \(T_{1}=60^{\circ} \mathrm{C}\), to state 2, where \(p_{2}=1.0\) MPa, during which the change in specific entropy is \(s_{2}-s_{1}=-0.035 \mathrm{\ kJ} / \mathrm{kg} \cdot \mathrm{K}\). At state 2, determine the temperature, in \({ }^{\circ} \mathrm{C}\), and the specific enthalpy, in kJ/kg.

ANSWER:

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We are required to calculate the temperature and specific enthalpy.

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