Applying the Entropy Balance: Closed SystemsA 2.64-kg

Chapter 6, Problem 64P

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

A 2.64-kg copper part, initially at 400 K, is plunged into a tank containing 4 kg of liquid water, initially at 300 K. The copper part and water can be modeled as incompressible with specific heats \(0.385 \mathrm{\ kJ} / \mathrm{kg} \cdot \mathrm{K}\) and \(4.2 \mathrm{\ kJ} / \mathrm{kg} \cdot \mathrm{K}\), respectively. For the copper part and water as the system, determine (a) the final equilibrium temperature, in K, and (b) the amount of entropy produced within the tank, in kJ/K. Ignore heat transfer between the system and its surroundings.

Questions & Answers

QUESTION:

A 2.64-kg copper part, initially at 400 K, is plunged into a tank containing 4 kg of liquid water, initially at 300 K. The copper part and water can be modeled as incompressible with specific heats \(0.385 \mathrm{\ kJ} / \mathrm{kg} \cdot \mathrm{K}\) and \(4.2 \mathrm{\ kJ} / \mathrm{kg} \cdot \mathrm{K}\), respectively. For the copper part and water as the system, determine (a) the final equilibrium temperature, in K, and (b) the amount of entropy produced within the tank, in kJ/K. Ignore heat transfer between the system and its surroundings.

ANSWER:

Solution 64P

Step 1 of 4

Here, the objective is to find the final equilibrium temperature when a Copper part is plunged in a tank. Also, we need to find the amount of entropy produced within the tank.

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back