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Using Isentropic Processes/EfficienciesAir at 25°C, 100
Chapter 6, Problem 148P(choose chapter or problem)
Air at \(25^{\circ} \mathrm{C}\), 100 kPa enters a compressor operating at steady state and exits at \(260^{\circ} \mathrm{C}\), 650 kPa. Stray heat transfer and kinetic and potential energy effects are negligible. Modeling air as an ideal gas with k = 1.4, determine the isentropic compressor efficiency.
Questions & Answers
QUESTION:
Air at \(25^{\circ} \mathrm{C}\), 100 kPa enters a compressor operating at steady state and exits at \(260^{\circ} \mathrm{C}\), 650 kPa. Stray heat transfer and kinetic and potential energy effects are negligible. Modeling air as an ideal gas with k = 1.4, determine the isentropic compressor efficiency.
ANSWER:Step 1 of 2
We have to determine the isentropic compressor efficiency of air at 25°C, 100 kPa which enters a compressor operating at steady state and exits at 260°C, 650 kPa.
The isentropic compressor of efficiency is given by the expression
where,
is the specific heat constant and it is given by
Thus,
=
=