Students doing community service. In a sample of 159,949 first-year college students, the National Survey of Student Engagement reported that 39% participated in community service or volunteer work.11 (a) Find the margin of error for 99% confidence. (b) Here are some facts from the report that summarizes the survey. The students were from 617 four-year colleges and universities. The response rate was 36%. Institutions paid a participation fee of between $1800 and $7800 based on the size of their undergraduate enrollment. Discuss these facts as possible sources of error in this study. How do you think these errors would compare with the margin of error that you calculated in part (a)?
3.1 Ans12) (a) Mean = Sum of all values divided by the number of values. Mean = ∑ x /n = 23/5 = 4.6 In order to calculate the median, we arrange the set of numbers in increasing order: 2 2 3 6 10. As the number of observations are odd, therefore median is the third value which is 3. Median = 3. Mode is the number that occurs most frequently in the given data. In this case, 2 occurs most frequently. So, mode is 2. (b)As per the question, we add 5 to each of the data values. New data set: 7 7 8 11 15. Mean = ∑ x /n = 48/5 = 9.6 In order to calculate the median, we arrange the set of numbers in increasing order: 7 7 8 11 15. As the number of observations are odd, median is the middle value which is the third value in this case. Median = 8. Mode is the number that occurs mos
