A random sample of size n = 121 yielded = .88.a. Is the

Step 1 of 3

a) we have to tell that the sample size is large enough for finding the confidence intervals for p

Given that  n = 121 and \(\widehat{p}=0.88\)

Here 

\(\begin{array}{c}
\widehat{q}=1-\widehat{p} \\
\quad=1-0.88 \\
=0.12
\end{array}\)

Now \(n \widehat{p}=121(0.88)=106.48\)

And \(n \widehat{q}=121(0.12)=14.52\)

here \(n \widehat{q}\) value is less than 15

Hence the sample size is not large enough to conclude the normal approximation is reasonable