Suppose you fit the first-order modely = ? 0 + ? 1 x 1 + ?

Chapter 12, Problem 7E

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QUESTION:

Suppose you fit the first-order model

\(y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{3}+\beta_{4} x_{4}+\beta_{5} x_{5}+\varepsilon\)

to n = 30 data points and obtain

\(SSE=.33\ \ \ \ \ R^2=.92\)

a. Do the values of SSE and \(R^2\) suggest that the model provides a good fit to the data? Explain.

b. Is the model of any use in predicting y? Test the null hypothesis \(H_0:\ \beta_1=\ \beta_2\ =\ \beta_3\ =\ \beta_4\ =\ \beta_5\ =\ 0\) against the alternative hypothesis \(H_a:\) At least one of the parameters \(\beta_1,\ \beta_2,\ .\ .\ .\ ,\ \beta_5\) is nonzero. Use \(\alpha\ =\ .05\).

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QUESTION:

Suppose you fit the first-order model

\(y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{3}+\beta_{4} x_{4}+\beta_{5} x_{5}+\varepsilon\)

to n = 30 data points and obtain

\(SSE=.33\ \ \ \ \ R^2=.92\)

a. Do the values of SSE and \(R^2\) suggest that the model provides a good fit to the data? Explain.

b. Is the model of any use in predicting y? Test the null hypothesis \(H_0:\ \beta_1=\ \beta_2\ =\ \beta_3\ =\ \beta_4\ =\ \beta_5\ =\ 0\) against the alternative hypothesis \(H_a:\) At least one of the parameters \(\beta_1,\ \beta_2,\ .\ .\ .\ ,\ \beta_5\) is nonzero. Use \(\alpha\ =\ .05\).

ANSWER:

Step 1 of 4

In least square prediction equation method,  denotes the fraction of the sample variation of the values of y. Thus, = 0 denotes the complete mismatch to the model and = 1 denotes the perfect match to the model. In other words, the greater the value of R2, the better the data fits into the model.

Hence here we have= 0.92 and SSE= 0.33

 

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