Phosphate baking powder is a mixture of starch, sodium

Modern Chemistry: Student Edition 2012 | 1st Edition | ISBN: 9780547586632 | Authors: Jerry L. Sarquis, Mickey Sarquis

Problem 9.1.45 Chapter 9

Modern Chemistry: Student Edition 2012 | 1st Edition

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Modern Chemistry: Student Edition 2012 | 1st Edition | ISBN: 9780547586632 | Authors: Jerry L. Sarquis, Mickey Sarquis

Modern Chemistry: Student Edition 2012 | 1st Edition

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Problem 9.1.45

Phosphate baking powder is a mixture of starch, sodium hydrogen carbonate, and calcium dihydrogen phosphate. When mixed with water, phosphate baking powder releases carbon dioxide gas, causing a dough or batter to bubble and rise. 2NaHCO3(aq) + Ca(H2PO4)2(aq) Na2HPO4(aq) + CaHPO4(aq) + 2CO2(g) + 2H2O(l) If 0.750 L CO2 is needed for a cake, and each kilogram of baking powder contains 168 g of NaHCO3, how many grams of baking powder must be used to generate this amount of CO2? The density of CO2 at baking temperature is about 1.20 g/L. 3

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Textbook: Modern Chemistry: Student Edition 2012
Edition: 1
Author: Jerry L. Sarquis, Mickey Sarquis
ISBN: 9780547586632

Modern Chemistry: Student Edition 2012 was written by and is associated to the ISBN: 9780547586632. This full solution covers the following key subjects: . This expansive textbook survival guide covers 98 chapters, and 1789 solutions. The answer to “Phosphate baking powder is a mixture of starch, sodium hydrogen carbonate, and calcium dihydrogen phosphate. When mixed with water, phosphate baking powder releases carbon dioxide gas, causing a dough or batter to bubble and rise. 2NaHCO3(aq) + Ca(H2PO4)2(aq) Na2HPO4(aq) + CaHPO4(aq) + 2CO2(g) + 2H2O(l) If 0.750 L CO2 is needed for a cake, and each kilogram of baking powder contains 168 g of NaHCO3, how many grams of baking powder must be used to generate this amount of CO2? The density of CO2 at baking temperature is about 1.20 g/L. 3” is broken down into a number of easy to follow steps, and 92 words. The full step-by-step solution to problem: 9.1.45 from chapter: 9 was answered by , our top Chemistry solution expert on 01/04/18, 09:13PM. Since the solution to 9.1.45 from 9 chapter was answered, more than 302 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Modern Chemistry: Student Edition 2012, edition: 1.

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