Show that the linearization of (4) at .5; 0/ is u0 D 5u5v,

Chapter , Problem 12

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Show that the linearization of (4) at .5; 0/ is u0 D 5u5v, v0 D 3v. Then show that the coefficient matrix of this linear system has the negative eigenvalue 1 D 5 and the positive eigenvalue 2 D 3. Hence .5; 0/ is a saddle point for the system in (4). 1

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