Solution Found!

Show that the nilpotent elements of a commutative ring

Chapter 13, Problem 16E

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

Problem 16E

Show that the nilpotent elements of a commutative ring form a subring.

Questions & Answers

QUESTION:

Problem 16E

Show that the nilpotent elements of a commutative ring form a subring.

ANSWER:

                                                       

Step 1 of 6

A ring R is a set with two binary operations such as addition and multiplication that satisfies several properties.

R is an Abelian group under addition and multiplication operation satisfies the associative law.

According to distributive laws

For every

This identity of the addition operation is denoted 0. If the multiplication operation has an identity it is called a unity. If multiplication is commutative we say that R is commutative.

A subring of a ring R is a subset

That is a ring under the operations of R.

Let a be an element of a ring R. The element a is a nilpotent if and only if there exists a positive integer  with

.

                                                         

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back